FYP 1 Week 14 : Preliminary Result
Date: 2 / 5 / 2018 ( Wednesday )
Title: Preliminary Result
Today we are performing the second test on our sound sensor. Back in our first test, we collected the charactheristic of the alarm sound (frequency) from Philips bedside monitor for Spo2 with several conditions.
The conditions are
Since we managed to record the frequencies of all condition type of alarm , thus we start do the testing on the repeatation of the alarm sound’s signals.The purpose of doing this experiment is to observe the consistency of the amplitude and frequency of the sound wave captured from the alarm sound.Besides that, this experiment also focusing on detecting the consistency of the alarm sounded when the same error was being triggered.
A function generator used to supply 10 V power to the sound sensor, while oscilloscope was used to display the resulting waveform when sound was detected.The probe was used to connect the output from sound sensor to the oscilloscope.
We will start the repeatation test with the Non-Pulsatile condition.
Firstly, we managed to obtained the average amplitude of of non- pulsatile condition signal
The value of average amplitude of non-pulsatile condition signal is 952 mV
Next,for the frequency of the pulse cycle and the time delay, there is some illustration to make reader to understand more about our finding results.
PULSE CYCLE SIGNALS RESULTS
For measuring the pulse cycle results, we set the oscilloscope with 500 mV/ div and 100ms/div.
1.Pulse Cycle 1 signal
Frequency : 4.808 Hz
Time(ms) : 208.0 ms
2.Pulse Cycle 2 signal
Frequency : 5.319 Hz
Time(ms) : 188 ms
3.Pulse Cycle 3 signal
Frequency : 5.000 Hz
Time(ms) : 200.0 ms
If we sum up all three results and divide it by 3 , we can get the average value of frequency and the time.
Average frequency (Hz) = (4.808 +5.319 +5.000)/3 = 5.042 Hz
Time(ms) = 1/ 5.042Hz = 198.33 ms
Thus, we can assumed that Non-Pulsatile alarm condition will produced alarm sound with frequency approximately with the value 5.042 Hz and the time 198.33 ms.
Today we are performing the second test on our sound sensor. Back in our first test, we collected the charactheristic of the alarm sound (frequency) from Philips bedside monitor for Spo2 with several conditions.
The conditions are
- Have Pulse
- Non-Pulsatile
- No Sensor
- Desat (SpO2)
- HR Low
- Noise from Cooling Fan of the Monitor
Since we managed to record the frequencies of all condition type of alarm , thus we start do the testing on the repeatation of the alarm sound’s signals.The purpose of doing this experiment is to observe the consistency of the amplitude and frequency of the sound wave captured from the alarm sound.Besides that, this experiment also focusing on detecting the consistency of the alarm sounded when the same error was being triggered.
A function generator used to supply 10 V power to the sound sensor, while oscilloscope was used to display the resulting waveform when sound was detected.The probe was used to connect the output from sound sensor to the oscilloscope.
We will start the repeatation test with the Non-Pulsatile condition.
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Picture 1 : the signal we will observed , 3 cycle sound signals and 2 time delay between signals. |
Firstly, we managed to obtained the average amplitude of of non- pulsatile condition signal
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Picture 2: The average amplitude of non-pulsatile condition signal is obtained |
Next,for the frequency of the pulse cycle and the time delay, there is some illustration to make reader to understand more about our finding results.
![]() |
Picture 3: We name the signal we captured to make the readers easy to understand our results. |
PULSE CYCLE SIGNALS RESULTS
For measuring the pulse cycle results, we set the oscilloscope with 500 mV/ div and 100ms/div.
1.Pulse Cycle 1 signal
Frequency : 4.808 Hz
Time(ms) : 208.0 ms
2.Pulse Cycle 2 signal
Frequency : 5.319 Hz
Time(ms) : 188 ms
3.Pulse Cycle 3 signal
Frequency : 5.000 Hz
Time(ms) : 200.0 ms
If we sum up all three results and divide it by 3 , we can get the average value of frequency and the time.
Average frequency (Hz) = (4.808 +5.319 +5.000)/3 = 5.042 Hz
Time(ms) = 1/ 5.042Hz = 198.33 ms
Thus, we can assumed that Non-Pulsatile alarm condition will produced alarm sound with frequency approximately with the value 5.042 Hz and the time 198.33 ms.
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